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The Tour Report

October 4 2013

6:55 PM

Mickelson-Bradley (U.S.) def. Day-DeLaet (Int'l), 4 and 3

Phil Mickelson chips to within three feet on the par-5 15th to set up Keegan Bradley's birdie putt to win. The pair won 4 and 3 after being up by six earlier in the match.

DUBLIN, Ohio -- The American duo of Phil Mickelson and Keegan Bradley bounced back from their Four-ball loss to crush the International duo of Jason Day and Graham DeLaet, 4 & 3, in their Foursomes match Friday at The Presidents Cup.


For the second straight match, Day and Delaet won the first hole with a birdie. They maintained the lead until Bradley drove the green at the par-5 fifth and Mickelson holed the eagle putt from 15 feet to square the match. That started a run of four consecutive holes won by the Americans, the latter three with birdies. The U.S. was 3 up at the turn and the International team couldn't keep pace. Two International bogeys sandwiched by an American birdie put Mickelson-Bradley 6 up through 12. At that point, they were 7 under for their round. Bradley's short missed par putt at the 13th followed by a wayward drive at the 14th only prolonged the inevitable.


Phil Mickelson. Could argue that his playing partner was just as valuable, at least through the first 12 holes when the Americans sprinted out to a big lead.


U.S. Category Int'l
7 Holes won 3
9 Holes led 4
1 Eagles 0
6 Birdies 5
2 Bogeys/worse 2

Click here for hole-by-hole recap of this match

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