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The Tour Report

October 3 2013

6:35 PM

Oosthuizen-Schwartzel (Int'l) def. Mickelson-Bradley (U.S.), 2 & 1

DUBLIN, Ohio -- The International duo of Louis Oosthuizen and Charl Schwartzel handed the American duo of Phil Mickelson and Keegan Bradley their first loss in team competition, winning 2 & 1 in Thursday's Four-ball match at The Presidents Cup.


Mickelson and Bradley were 2 up through seven and seemed to be on the way to a fourth straight win, having won all three of their matches last year at the Ryder Cup. But the South Africans won three of the next four holes with birdies and never trailed after that. "I think we did proper better-ball," Oosthuizen said. "When he was out of the hole, I played well. When I was out of it, he hit some amazing shots." Bradley has an eagle-three at the seventh hole but otherwise left Mickelson to do the bulk of the work.


Charl Schwartzel. Had four birdies on the front nine and then finished strong with three birdies in the final five holes.


U.S. Category Int'l
3 Holes won 5
6 Holes led 7
1 Team eagles 0
5 Team birdies 9
0 Team bogeys/worse 0

Click here for hole-by-hole recap of this match

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